📖 9 min read📅 Updated: 2 May 2026

Algebra carries the single largest weighting on the Higher Tier paper (30%) and represents 20% of Foundation Tier marks. Mastering algebraic manipulation is key to unlocking top GCSE grades.

1. Expanding Brackets & Factorising

Factorising is the inverse operation of expanding brackets.

Key Factorising Patterns

  • Single Bracket (Common Factor): 6x² + 9x = 3x(2x + 3).
  • Difference of Two Squares (DOTS): a² - b² = (a - b)(a + b). E.g. x² - 49 = (x - 7)(x + 7).
  • Quadratic Trinomial (x² + bx + c): Find two numbers that multiply to c and add to b. E.g. x² + 5x + 6 = (x + 2)(x + 3).

2. Solving Quadratic Equations

Every quadratic equation must be arranged into the form ax² + bx + c = 0 before solving.

MethodWhen to UseFormula / Rule
FactorisingWhen the quadratic splits easily into integer factors.Set each factor bracket equal to zero.
Quadratic FormulaWhen factors are non-integers or when asked for decimal answers (e.g. 2 d.p.).x = (-b ± √(b² - 4ac)) / (2a)
Completing the SquareWhen finding the turning point (h, k) of a parabola.x² + bx + c = (x + b/2)² - (b/2)² + c
💡 Key Takeaway

The turning point of y = (x + p)² + q is always (-p, q). This is a guaranteed 2-mark question on Higher tier papers!

3. Sequences: Linear & Quadratic nth Term

Linear Sequences

Has a constant 1st difference d. The nth term formula is dn + c, where c is the zero term (T₀).

Quadratic Sequences (Higher)

Has a constant 2nd difference.

  1. Find 2nd difference. Divide by 2 to find a in an² + bn + c.
  2. Subtract an² from sequence terms to leave a linear remainder sequence.
  3. Find nth term of remainder to determine b and c.

4. Graph Transformations (y = f(x))

TransformationEffect on GraphCoordinate Change (x, y)
y = f(x) + aTranslate vertically UP by a(x, y + a)
y = f(x - a)Translate horizontally RIGHT by a(x + a, y)
y = -f(x)Reflect across the x-axis(x, -y)
y = f(-x)Reflect across the y-axis(-x, y)

Frequently Asked Questions

For any quadratic equation in the form ax² + bx + c = 0, x = (-b ± √(b² - 4ac)) / (2a). Make sure to state values of a, b, and c clearly before substituting into your calculator.

Find the 2nd difference. Divide the 2nd difference by 2 to get 'a' in an² + bn + c. Subtract an² from each term in the original sequence to get a linear sequence, then find its nth term to determine 'b' and 'c'.

f(x + a) shifts (translates) the graph horizontally to the LEFT by 'a' units. Notice that inside the bracket, addition shifts left (-a, 0) and subtraction shifts right (+a, 0).